Question

For the following exercise, consider this scenario: A town's population has been increasing at a constant rate. In 2010 the population was 45000 . By 2012 the population had increased to 51250 . Assume this trend continues linearly. Predict the population in 2016.

Answer 1

scenario preiod

Explanation:

Answer 2

63,750

Explanation:

#Calculate the rate of change per year:

`\bigtriangleup=(2012 \ pop- 2010\ pop)/(2012-2010)\\\\=(51250-4500)/(2)\\\\=3125`

The population increasing by a constant of 3125 per year.

-Let x be the time in years

-The general form of a linear equation is

`y=mx+c, c=45000\\\\\therefore y=mx\\\\y(x)=3125x+45000`

The population in 2016 is therefore predicted as:

`y=mx+c\\\\y(2016-2010)=3125x+45000\\\\y(6)=3125* 6+45000\\\\=63750`

Hence, the population in 2016 is 63,750