Answer:
ISCOCELES TRIANGLE
Explanation:
<BAC is alternate to <ACD and <ABC is alternate to <BCE
So, <BAC = <ACD = 50° and <BCE = <ABC = 80°
<ACD + <ACB +<BCE =180 (sum of angles in a straight line)
50° + <ACB + 80 = 180
<ACB = 180-(80+50)
<ACB = 180 - 130 = 50°
You can see that the base angles <BAC and <ACB are equal(<BAC =50° and <ACB = 50°), so the triangle is an Iscoceles triangle.