Question

Calculate the molar solubility of CaSO4. Ksp = 7.10 x 10-5

Answer 1

Multiple or divide them

Answer 2

Answer: The solubility of calcium sulfate is
`8.43* 10^(-3)M`

Step-by-step explanation:

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

The chemical equation for the ionization of calcium sulfate follows:

`CaSO_4(aq.)\rightleftharpoons Ca^(2+)(aq.)+SO_4^(2-)(aq.)`

s s

The expression of
`K_(sp)` for above equation follows:

`K_(sp)=s* s`

We are given:

`K_(sp)=7.10* 10^(-5)`

Putting values in above expression, we get:

`7.10* 10^(-5)=s* s\\\\s=\sqrt{7.10* 10^(-5)}=8.43* 10^(-3)M`

Hence, the solubility of calcium sulfate is
`8.43* 10^(-3)M`