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Read and solve the problem below: <1, <2, and <3 form a straight line. If m<3 is six more than twice m<1 and m<2 is 27 less than m<3, find m<2

User Ross Moody
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1 Answer

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Answer:


m\angle 2=57^(\circ)

Explanation:

Let x represent measure of angle 1.

We have been given that measure of angle 3 is six more than twice the measure of angle 1. So measure of angle 3 would be
2x+6.

We are also told that measure of angle 2 is 27 less than measure of angle 3, so measure of angle 2 would be
2x+6-27\Rightarrow 2x-21.

We have been given that angle 1, angle 2 and angle 3 form a straight line, so the sum of angles 1, 2 and 3 would be 180 degrees.


m\angle 1+m\angle 2+m\angle 3=180^(\circ)

Upon substituting the expressions for measure of angles, we will get:


x+2x-21+2x+6=180

Now, we will combine like terms.


5x-15=180


5x-15+15=180+15


5x=195


(5x)/(5)=(195)/(5)


x=39

The measure of angle 2 would be
2x-21\Rightarrow 2(39)-21=78-21=57.

Therefore, the measure of angle 2 is 57 degrees.

User Scott Simontis
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