Question

Find the area of △ABC with side lengths b = 6 and c = 17, and included angle A = 135∘. Round your answer to the nearest tenth

SOME ONE HELP ME SOLVE THIS PLEASE

Answer 1

................................

Explanation:

Answer 2

Area = 36.1 sq. units

Explanation:

We will use the "included angle area" formula for a triangle to solve this problem.

The formula is:

`A=(1)/(2)abSinC`

Where

a and b are the two sides given

C is the angle given BETWEEN the two sides

From the problem, we can write:

the two sides are 6 & 17, so that will be "a" and "b" of the formula

the included angle is 135, so that will be "C" of the formula

Substituting, we find the answer:

`A=(1)/(2)abSinC\\A=(1)/(2)(6)(17)Sin(135)\\A=36.06`

Rounded to 1 decimal place,

Area = 36.1 sq. units