Final answer:
To find the heat released when 225.0 g of water cools from 85.5°C to 50.0°C, use the formula Q = mcΔT with the specific heat of water at 4.184 J/g°C and the temperature change of 35.5°C.
Step-by-step explanation:
To calculate the amount of heat released by water when it cools down, you can use the formula Q = mcΔT, where 'Q' is the heat energy, 'm' is the mass of the water, 'c' is the specific heat capacity of water, and 'ΔT' is the change in temperature. The specific heat of water is given as 4.184 J/g°C. For 225.0 g of water cooling from 85.5°C to 50.0°C, the change in temperature 'ΔT' is 85.5°C - 50.0°C = 35.5°C. Plugging these values into the formula gives Q = 225.0 g × 4.184 J/g°C × 35.5°C, which calculates the heat released during the cooling process.