Answer:
The number of messages that will cost same both plans is 1000.
Explanation:
Given,
For 1st offer:
Total number of messages = 500
Charge of each message after 500 messages = $0.10
For 2nd offer:
Total number of messages = 400
Charge of each message after 400 messages = $0.20
We need to find out the number of messages can be sent for equal cost of both plans.
Solution,
Let the number of messages be 'm'.
So For 1st offer:
Total cost 'c' is equal to fixed cost for 500 messages plus charge of each message multiplied with number of messages.
framing in equation form, we get;
![c=500+0.10m](https://img.qammunity.org/2021/formulas/mathematics/middle-school/7gm3xs8oe3hnmdhbsbwmmhdwze0mb8xjxr.png)
Again for 2nd offer:
Total cost 'c' is equal to fixed cost for 400 messages plus charge of each message multiplied with number of messages.
framing in equation form, we get;
![c=400+0.20m](https://img.qammunity.org/2021/formulas/mathematics/middle-school/em82v7yvdbc8ux54tbmi60qnbooqnlfee1.png)
Now the question said that the charge would be the same.
So we can say that;
![500+0.10m=400+0.20m](https://img.qammunity.org/2021/formulas/mathematics/middle-school/urxka5jdtyvnmdpe2gnoit5a3pokeca3nx.png)
On combining the like terms, we get;
![500-400=0.20m-0.10m\\\\100=0.1m\\\\](https://img.qammunity.org/2021/formulas/mathematics/middle-school/bt9cgrmmkll5aun869i9ybss4ca2berual.png)
Now using multiplication property, we will multiply both side by '10' and get;
![100* 10=0.1m*10\\\\1000=m](https://img.qammunity.org/2021/formulas/mathematics/middle-school/s3pt8zmz3svikxdl5883zdvy7hbls1f69v.png)
Hence The number of messages that will cost same both plans is 1000.