Question

A sample of N2 is placed into a 50ml flask for analysis. At 27°C, the samples pressure is 80 kPa. If the sample is cooled until exerts a pressure of 53 kPa, what is the temperature of the gas?

Answer 1

198.8K

Step-by-step explanation:

Given parameters:

Constant volume = constant mole = 50mL

T₁ = 27°C, which gives 27 + 273 = 300K

P₁ = 80kPa

P₂ = 53kPa

T₂ =?

Solution:

Devolving the combined gas law and assuming constant volume, we can solve this problem. The expression obtained will give us a relationship between pressure and temperature.

At constant volume, the pressure of a given mass of gas varies directly with the absolute temperature;

mathematically;

`(P_(1) )/(T_(1) ) = (P_(2) )/(T_(2) )`

input the parameters and solve for T₂;

`(80)/(300)` =
`(53)/(T_(2) )`

T₂ = 198.8K