Answer:
its actually -2
Explanation:
The difference of the square of a number and 10 is equal to 3 times that number. Find the negative solution.
3\text{ times that number}\rightarrow 3x
3 times that number→3x
\text{Difference of the square of a number and } 10\rightarrow x^2-10
Difference of the square of a number and 10→x
2
−10
x^2-10=
x
2
−10=
\,\,3x
3x
-3x=
−3x=
\,\,-3x
−3x
x^2-3x-10=0
x
2
−3x−10=0
Set to Zero
(x-5)(x+2)=0
(x−5)(x+2)=0
Factor
x-5=0 \hspace{30px} x+2=0
x−5=0x+2=0
Set factors to zero
x=5 \hspace{40px} x=-2
x=5x=−2
\text{Negative Solution: }-2
Negative Solution: −2
(i had the same question and copied the explanation off of Delta Math)