Question

The larger of two numbers is eight more than three times the smaller number. The sum of the two numbers is 48. Find the two numbers

Answer 1

The larger number is eight more than three times the smaller number. The sum of the two numbers is 48. The two numbers are 38 and 10.

Step-by-step explanation:

Let's represent the two numbers as x and y. We are given that the larger number is eight more than three times the smaller number, so we can write the equation:

x = 3y + 8

We are also given that the sum of the two numbers is 48, so we can write the equation:

x + y = 48

Now, we can solve this system of equations. Substituting the value of x from the first equation into the second equation:

(3y + 8) + y = 48

Combining like terms:

4y + 8 = 48

Subtracting 8 from both sides:
4y = 40

Dividing both sides by 4:

y = 10

Substituting y = 10 back into the first equation to find x:

x = 3(10) + 8 = 38

Therefore, the two numbers are 38 and 10.

Answer 2

Answer: the smaller number is 8. The larger number is 38

Step-by-step explanation:

Let x represent the smaller number.

The The larger of the two numbers is eight more than three times the smaller number. It means that the larger number is 3x + 8

The sum of the two numbers is 48. It means that

x + 3x + 8 = 48

4x + 8 = 48

4x = 48 - 8 = 40

x = 40/4 = 10

Substituting x = 10 into 3x + 8, it becomes

3 × 10 + 8 = 38