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What are solutions of 3x2+14x+16=0?p

User Meera Tank
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1 Answer

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Answer:

x =(14-√388)/6=(7-√ 97 )/3= -0.950

x =(14+√388)/6=(7+√ 97 )/3= 5.616

explanation: Equation at the end of step 1 :

(3x2 - 14x) - 16 = 0

Step 2 :

Trying to factor by splitting the middle term

2.1 Factoring 3x2-14x-16

Equation at the end of step 2 :

3x2 - 14x - 16 = 0

Step 3 :

Parabola, Finding the Vertex :

3.1 Find the Vertex of y = 3x2-14x-16

Add 7/3 to both sides to obtain:

x = 7/3 + √ 97/9

Since a square root has two values, one positive and the other negative

x2 - (14/3)x - (16/3) = 0

has two solutions:

x = 7/3 + √ 97/9

or

x = 7/3 - √ 97/9

Note that √ 97/9 can be written as

√ 97 / √ 9 which is √ 97 / 3

Solve Quadratic Equation using the Quadratic Formula

3.3 Solving 3x2-14x-16 = 0 by the Quadratic Formula .

According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :

- B ± √ B2-4AC

x = ————————

2A

In our case, A = 3

B = -14

C = -16

Accordingly, B2 - 4AC =

196 - (-192) =

388

Applying the quadratic formula :

14 ± √ 388

x = ——————

6

Can √ 388 be simplified ?

Yes! The prime factorization of 388 is

2•2•97

To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).

√ 388 = √ 2•2•97 =

± 2 • √ 97

User Algiogia
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