Question

Find the smallest integer that satisfies the inequalities

a. 4x - 15 > x + 8
b. 2x + 13 >7x

Answer 1

The answer is a. x>23/3

Answer 2

a. x> 23 /3

b: x< 13/5

Explanation:

A: Step 1: Subtract x from both sides.

4x−15−x>x+8−x

3x−15>8

Step 2: Add 15 to both sides.

3x−15+15>8+15

3x>23

Step 3: Divide both sides by 3.

x> 23/3

B: Step 1: Subtract 7x from both sides.

2x+13−7x>7x−7x

−5x+13>0

Step 2: Subtract 13 from both sides.

−5x+13−13>0−13

−5x>−13

Step 3: Divide both sides by -5.

Answer: x< 13/5