1 Answer

Dyasta · Answer 1 · 2021-03-14T04:23:18+0000

Answer:

Part 1)

$\tau_1 = 5 * (0.50) = 2.5 N m$

Part 2)

$\tau_2 = 14 * (0.30) = 4.2 N m$

Part 3)

$\tau_3 = 1.4 N m$

Part 4)

Since torque on right side is more so here it will turn and slip over it

Step-by-step explanation:

As we know that the block A is placed at distance

d = 50 cm from the hinge at 70 cm mark

So torque due to weight of A is given as

$\tau_1 = 5 * (0.50) = 2.5 N m$

the block B is placed at distance

d = 30 cm from the hinge at 70 cm mark

So torque due to weight of B is given as

$\tau_2 = 14 * (0.30) = 4.2 N m$

Now torque due to weight of the scale is given as

$\tau_3 = 7(0.20)$

$\tau_3 = 1.4 N m$

now torque on left side of scale is given as

$\tau_(left) = \tau_1 + \tau_3$

$\tau_(left) = 2.5 + 1.4 = 3.9 N m$

Torque on right Side is given as

$\tau_(right) = \tau_2 = 4.2 Nm$

Since torque on right side is more so here it will turn and slip over it

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