Answer:
triangleBFCBis an isosceles triangle
angleBFC=90°
angle FBC and angle BCF are equal
let angle FBC=x,angleBCF=x
the sum of angles in a triangle=180°
90+x+x=180°
90+2x=180
2x=180-90
2x=90
divide both sides by 2
2x÷2=90÷2
x=45°
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