Question

What is the equation of the line that passes through the point (-6,-2) and has a slope of -1/6

Answer 1

Explanation:

Given

slope ( m) = -1/6

Point ( -6 , -2)

Now the equation of line is given by

y - y1 = m ( x - x1)

y +2 = -1/6 ( x + 6)

6(y + 2 ) = -1 ( x + 6)

6y + 12 = -x -6

x +6y +12 + 6 = 0

x + 6y +18 = 0

Which is the required equation of line