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A cylinder contains nitrogen and oxygen under 4.015 atm pressure. The partial pressure of N2 is 2.907 atm. What is the partial pressure of the water vapor? Group of answer choices

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Answer: The partial pressure of the water vapor is 1.108 atm

Step-by-step explanation:

According to Dalton's law, the total pressure of a mixture of gases is the sum of individual pressures exerted by the constituent gases.


p_(total)=p_A+p_B

Thus
p_(total)=p_(N_2)+p_(H_2O)

Given:
p_(total) =4.015 atm


p_(N_2)= 2.907 atm


p_(H_2O) = ?

Thus
4.015=2.907+p_(H_2O)


p_(H_2O)=1.108atm

Thus the partial pressure of the water vapor is 1.108 atm

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