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A sample of helium gas has a volume of 150. Ml (V₁) at 0.95 atom (P₁). What will your new pressure (P₁) be if the volume is changed to 40.0 ml (V₁) and temperature remains constant?

User Mabergerx
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1 Answer

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Answer: The new pressure when temperature remains constant is 3.56 atm

Step-by-step explanation:

To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is inversely proportional to the volume of the gas at constant temperature.

The equation given by this law is:


P_1V_1=P_2V_2

where,


P_1\text{ and }V_1 are initial pressure and volume.


P_2\text{ and }V_2 are final pressure and volume.

We are given:


P_1=0.95atm\\V_1=150mL\\P_2=?atm\\V_2=40.0mL

Putting values in above equation, we get:


0.95atm* 150mL=P_2* 40\\\\P_2=(0.95* 150)/(40)=3.56atm

Hence, the new pressure when temperature remains constant is 3.56 atm

User Andreas Reiff
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