Question

In an experiment, a student needs 250.0 mL of a 0.100 M copper (II) chloride solution. A stock solution of 2.00 M copper (II) chloride is available. How much of the stock solution is needed

Answer 1

Answer : The volume of stock solution needed are, 12.5 mL

Explanation :

Formula used :

`M_1V_1=M_2V_2`

where,

`M_1\text{ and }V_1` are the initial molarity and volume of copper (II) chloride.

`M_2\text{ and }V_2` are the final molarity and volume of stock solution of copper (II) chloride.

We are given:

`M_1=0.100M\\V_1=250.0mL\\M_2=2.00M\\V_2=?`

Putting values in above equation, we get:

`0.100M* 250.0mL=2.00M* V_2\\\\V_2=12.5mL`

Hence, the volume of stock solution needed are, 12.5 mL