Question

If 10.0 moles of O₂ are reacted with excess NO in the reaction below, and only 8.0 mol of NO₂ were collected, then what is the percent yield for the reaction?

2 NO (g) + O₂ (g) → 2 NO₂ (g)

Answer 1

Step-by-step explanation:

General Remarks

The balance numbers are the same. (The balance numbers are 2 and 2)

The balance number in front of the O2 is 1.

So for every mole of O2 needed 2 moles of NO2 should be produced.

If 10.0 moles of oxygen is used, then you should get 20 mols of NO2 should be produced.

Formula

% yield = (what was produced / what should have been produced) *100

Givens

What was produced = 7 moles

What should have been produced = 20 moles

Solution

Substitute the givens into the equation

% yield = 8/20 * 100

% yield = 0.40 * 100

Answer: 40%