Question

When sodium metal is added to water, the following reaction occurs: 2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g) What is the theoretical number of moles of hydrogen gas produced when 0.068 mol of sodium metal reacts?

Answer 1

`n_(H_2)^(Theoretical)=0.034molH_2`

Step-by-step explanation:

Hello,

In this case, based on the given rewritten reaction:

`2Na(s) + 2H_2O(l) \rightarrow 2NaOH(aq) + H_2(g)`

The stoichiometry leads to the following theoretical moles of oxygen:

`n_(H_2)^(Theoretical)=0.068molNa*(1molH_2)/(2molNa)=0.034molH_2\\n_(H_2)^(Theoretical)=0.034molH_2`

As sodium and hydrogen as a 2 to 1 molar relationship.

Best regards.