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What is the equation of the line that is parallel to the line 5X+

2Y= 12 and passage to the point -2, 4

1 Answer

3 votes

Explanation:

To determine the equation of the line parallel to
5x + 2y = 12, we need to first determine the slope of the given line.

A line in slope-intercept form is represented by the following:


y = mx + b

where
m is the slope of the line and
b is the y-intercept.

Rearranging the given line will give us the slope of the line:


5x + 2y = 12


2y = -5x + 12


y = -(5)/(2)x + 6

From this, since we know the lines are parallel, if the slope of the given line is
-(5)/(2), then the slope of the line we are constructing must also be
-(5)/(2).

We can now start to construct the line with the same slope-intercept form:


y = mx + b


y = -(5)/(2)x + b

To determine the y-intercept,
b, we can plug in the point
(-2, 4) since we are told from the problem statement that this parallel line runs through it:


y = -(5)/(2)x + b


4 = -(5)/(2)(-2) + b


4 = 5 + b


b = -1

Finally, we have our parallel line:


y = -(5)/(2)x - 1

If this line needs to be in standard form, we can rearrange it a little:


2y = -5x - 2


5x + 2y = -2

User Lingzhi Zhang
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