Answer: The volume of sulfur dioxide measured at STP is 125.44 L
Step-by-step explanation:
To calculate the number of moles, we use the equation:

Given mass of galena = 3.73 kg = 3730 g (Conversion factor: 1 kg = 1000 g)
Molar mass of galena = 239.3 g/mol
Putting values in above equation, we get:

To calculate the amount of oxygen gas, we use the equation given by ideal gas which follows:

where,
P = pressure of the gas = 2.00 atm
V = Volume of the gas = 170 L
T = Temperature of the gas =
![220^oC=[220+273]K=493K](https://img.qammunity.org/2021/formulas/chemistry/college/regnugt9t4w8l2f67wuorcrf7wh9kqh0px.png)
R = Gas constant =

n = number of moles of oxygen gas = ?
Putting values in above equation, we get:

The chemical equation for the reaction of lead (II) sulfide and oxygen gas follows:

By Stoichiometry of the reaction:
3 moles of oxygen gas reacts with 2 moles of galena
So, 8.4 moles of oxygen gas will react with =
of galena
As, given amount of lead (II) sulfide is more than the required amount. So, it is considered as an excess reagent.
Thus, oxygen gas is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
3 moles of oxygen gas produces 2 moles of sulfur dioxide
So, 8.4 moles of oxygen gas will produce =
of sulfur dioxide
At STP:
1 mole of a gas occupies 22.4 L of volume
So, 5.6 moles of sulfur dioxide will occupy =
of volume
Hence, the volume of sulfur dioxide measured at STP is 125.44 L