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The time for a professor to grade an exam is normally distributed with a mean of 16.3 minutes and a standard deviation of 4.2 minutes. What is the probability that a randomly selected exam will require less than 20 minutes to grade

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Answer:

81.06% probability that a randomly selected exam will require less than 20 minutes to grade

Explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean
\mu and standard deviation
\sigma, the zscore of a measure X is given by:


Z = (X - \mu)/(\sigma)

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:


\mu = 16.3, \sigma = 4.2

What is the probability that a randomly selected exam will require less than 20 minutes to grade

This is the pvalue of Z when X = 20.


Z = (X - \mu)/(\sigma)


Z = (20 - 16.3)/(4.2)


Z = 0.88


Z = 0.88 has a pvalue of 0.8106

81.06% probability that a randomly selected exam will require less than 20 minutes to grade

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