Question

A wire carrying a current of 2.85 A has a straight segment of 2.35 m. Determine the magnitude of the magnetic field due to this segment of wire at a point P which is at the midpoint of the straight segment of wire and a distance of 0.275 m perpendicular to the wire.

Answer 1

`2.02* 10^(-6) T`

Step-by-step explanation:

We are given that

Current,I=2.85 A

Length of segment=l=2.35 m

d=0.275 m

We have to find the magnitude of magnetic field due to this segment of wire at a point P which is at midpoint of the straight wire.

`r=(l)/(2)=(2.35)/(2)=1.175 m`

`\theta=tan^(-1)((r)/(d))=tan^(-1)((1.175)/(0.275))=76.82^(\circ)`

`\theta=\theta_1=\theta_2`

Magnetic field,B=
`(\mu_0I)/(4\pi d)(sin\theta_1+sin\theta_2)=(\mu_0I)/(4\pi d)(2sin\theta)`

Where
`(\mu_0)/(4\pi)=10^(-7)`

Using the formula

`B=(10^(-7)* 2.85)/(0.275)(2sin(76.82))=2.02* 10^(-6) T`