Question

The population that you're interested in has a mean of 60 and a standard deviation of 72 Step 2 of 2: If you calculate a(n) 93.12 % Confidence Interval on the Mean, what will your Margin of Error be? (Round to 2 decimal places.)

Answer 1

Z = 8.41

Explanation:

Given that standard deviation = 72

Mean = 60

Z = marginal error

Z = 72/√60

Z = 72/7.746

Z = (9.036)(0.9312)

Z = 8.41