819 ml is the volume the gas will occupy at 30.0°C.
Step-by-step explanation:
Data given:
initial volume of the gas V1 = 590 ml
initial temperature of the gas T1 = -55 degrees OR 218.15
final volume of the gas V2 = ?
final temperature of the gas T2 = 30 degrees OR 303.15
Charles' Law equation is used to calculate the volume of gas at 30 degrees from the data given in the question.
=
![(V2)/(T2)](https://img.qammunity.org/2021/formulas/chemistry/middle-school/pij9kcy1pqhxmm9i7dhaxdydnc1tw8e5rg.png)
V2 =
![(V1T2)/(T1)](https://img.qammunity.org/2021/formulas/chemistry/middle-school/hno8vnvin9iikbysrgmihazimmdk1t9adj.png)
V2 =
![(590 X 303.15)/(218.15)](https://img.qammunity.org/2021/formulas/chemistry/middle-school/qbjjfr3n2io4o08a2iad7czyd6hatuan8d.png)
V2 = 819 ml
The final volume of the gas would be 819 ml.