Question

A stone of mass 5g is projected with a rubber catapult. if the catapult is stretched through a distance of 7cm by an average force of 70 North, calculate the instantaneous velocity of the stone when released ​

Answer 1

Step-by-step explanation:

solution: mass m = 5g = 0.005kg; extension e = 7cm = 0.07m; force f = 70 N; velocity = ?; using: work done in elastic material w = 1/2 fe = 1/2 ke2 = 1/2 mv2 - the kinetic energy of the moving stone. 1/2 fe =...