Question

Please someone help!!!!

Kristine observes the top of a lookout tower from a point 220 ft from its base.

If the indicated angle of elevation measures 37º, how tall is the tower? Give your answer to the nearest tenth of a foot.

Answer 1

height of the tower: 165.8 ft

use tan rule:

`\sf \sf tan(x)= (opposite)/(adjacent)`

Here: [ your calculator should be in degree mode [D] ]

• x = 37°

• opposite = height of the tower

• adjacent = 220

Solve:

`\hookrightarrow \sf \sf tan(37)= (t)/(220)`

`\hookrightarrow \sf t = \sf tan(37)*220`

`\hookrightarrow \sf t = 165.8 \ ft`