Answer:
no
Explanation:
The sequence can be described by an exponential function with a base of 1.
a(n) = 1^n
This is what might be called a "degenerate" case. The function neither grows nor decays. While the terms do not diverge, their sum does.
__
Additional comment
It can also be described as an arithmetic sequence with a common difference of zero.
a(n) = 1 + 0·n