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Tyler says that the sequence 1, 1, 1,... Of repeating 1s is not exponential because it does not change. Do you agree with Tyler? Explain your reasoning.

User Nuno Costa
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1 Answer

6 votes

Answer:

no

Explanation:

The sequence can be described by an exponential function with a base of 1.

a(n) = 1^n

This is what might be called a "degenerate" case. The function neither grows nor decays. While the terms do not diverge, their sum does.

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Additional comment

It can also be described as an arithmetic sequence with a common difference of zero.

a(n) = 1 + 0·n

User Shenxian
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