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33 votes
33 votes
Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal places where appropriate. If there is no solution, enter NO SOLUTION.)

A). (tan(x) − 4)(9 sin^2(x) − 1) = 0

B). 3 sin(2x) − 4 sin(x) = 0

User Shadowman
by
2.8k points

1 Answer

18 votes
18 votes

Answer:

Explanation:

A)
(tanx-4)(9sin^2x-1)=0\\\\\\


9sin^2x-1=0\\\\sin^2x=(1)/(9) sinx=(1)/(3) or
sinx=(-1)/(3)

OR
tanx=4\\

B)


3sin2x=3.2.sinx.cosx\\\\6.sinx.cosx-4.sinx= 2sinx.(3cosx-2)=0\\\\3.cosx=2 cosx=(2)/(3)

User Hojberg
by
2.8k points