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The length of a rectangle is 6 m longer than its width.

If the perimeter of the rectangle is 40 m, find its area.

User Waygood
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2 Answers

1 vote

Answer:

=91 cm squared

Explanation:

LET THE WIDTH BE X

the length is therefore x+6

2(x)+2(x+6)=40

2x+2x+12=40

4x=28

x=7

area=7×7+6=91

User Bebe
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5 votes

Step 1: Let's denote the width of the rectangle as x. Therefore, the length will be x + 6.

Step 2: The formula to calculate the perimeter of a rectangle is:

Perimeter = 2 * (length + width)

We know the perimeter is 40m, so we can set up our equation like this:

40 = 2 * ((x + 6) + x)

Step 3: Distribute the 2 into the parenthesis (multiply every term inside the parenthesis by 2):

40 = 2 * (x + 6) + 2 * x

This simplifies further to:

40 = 2x + 12 + 2x

Step 4: Combine like terms which results in:

40 = 4x + 12

Step 5: Then, we isolate x. First, subtract 12 from both sides of the equation:

40 - 12 = 4x + 12 - 12

Simplifying that gives us:

28 = 4x

Step 6: Finally, to solve for x, divide both sides of the equation by 4:

x = 28 / 4, which gives us x = 7.

So the width of the rectangle is 7 meters.

Step 7: To find the length of the rectangle, we recall that the length is x + 6, therefore the length is 7 + 6 = 13 meters.

Step 8: The area of a rectangle is calculated using the formula:

Area = length * width

Substituting the values for the length and width yields:

Area = 13 * 7

This gives us an area of 91 square meters.

Therefore, the width of the rectangle is 7 m, its length is 13 m, and its area is

Answer: 91 m^2.

User MorningGlory
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