Question

A car driving on a straight track accelerates at a rate of 3.2 m/s^2 for 14 sec. If the initial velocity of the car was 5.1 m/s, and its initial position was 0 m, what is its final position?

-385m
32m
385m
242.2m
-242.2m

Answer 1

The final position of the car is 385 m.

Step-by-step explanation:

We know the formula :

s =
`ut +`
`(1)/(2) at^(2)`

where,

s = distance

u = initial velocity = 5.1 m/s

t = time taken = 14 sec

a = acceleration = 3.2 m/
`s^(2)`

Solving:

s = 5.1* 14 +
`(1)/(2)` * 3.2 *
`14^(2)`

∴ s = 385 m

Hence the final position of the car is 385 m.