Question

Use the following equation to calculate the number of moles of Ag that are formed from 3.54 g of Cu completely reacting with excess AgNO3. Use the table of molar masses below.

Cu + 2 AgNO3 --> Cu(NO3)2 + 2 Ag
HELP ASAP my test has a timer!!

Answer 1

0.12 moles of Ag are produced.

Step-by-step explanation:

Given data:

Mass of Cu = 3.54 g

Moles of Ag produced = ?

Solution:

Chemical equation:

Cu + 2 AgNO₃ → Cu(NO₃)₂ + 2Ag

Number of moles of Cu:

Number of moles = mass /molar mass

Number of moles = 3.54 g/ 63.55 g/mol

Number of moles = 0.06 mol

Now we will compare the moles of Cu with Ag.

Cu : Ag

1 : 2

0.06 : 2×0.06 = 0.12 mol