Answer:
The correct answer is 4∛10 cm.
Explanation:
The manufacturer sells super soups in cylindrical cans of height (h) of 10 cm and radius (r) 4 cm.
Volume of the old cylindrical cans = π ×
× h = π × 16 × 10 = 160π
.
The manufacturer re brands the soup as square meal soup in cans containing the same volume of soup as before.
Given the height and diameter of this new can is equal say a cm.
Radius of the new can is
.
Volume of the new can is π ×
× a = π ×
Now given that these two volumes are equal.
∴ π ×
= 160π
⇒
= 160 × 4
⇒ a = 4∛10
Thus the new height of the soup can is 4∛10 cm.