Question

(2k^3-7k^2+3k) -(-4k^2+5k)=(2k
3
−7k
2
+3k)−(−4k
2
+5k)=

Answer 1

k = 1

k = 0

Explanation:

Equation at the end of step 1 :

((((2•(k3))-(7•(k2)))+3k)-((0-(4•(k2)))+5k))-((((2•(k3))-7k)+3k)-((0-22k2)+5k)) = 0

Step 2 :

Equation at the end of step 2 :

((((2•(k3))-(7•(k2)))+3k)-((0-(4•(k2)))+5k))-(((2k3-7k)+3k)-(5k-4k2)) = 0

Step 3 :

Equation at the end of step 3 :

((((2•(k3))-(7•(k2)))+3k)-((0-22k2)+5k))-(2k3+4k2-9k) = 0

Step 4 :

Equation at the end of step 4 :

((((2•(k3))-7k2)+3k)-(5k-4k2))-(2k3+4k2-9k) = 0

Step 5 :

Equation at the end of step 5 :

(((2k3 - 7k2) + 3k) - (5k - 4k2)) - (2k3 + 4k2 - 9k) = 0

Pulling out like terms :

7.1 Pull out like factors :

7k - 7k2 = -7k • (k - 1)

Equation at the end of step 7 :

-7k • (k - 1) = 0