Question

How much heat energy must be added to 52kg Of water at 68°F to raise the temperature to 212°F? The specific heat capacity for water is 4.186×10 to the third power J/kg times degrees Celsius

Answer 1

The amount of energy added to rise the temperature Q = 17413.76 KJ

Step-by-step explanation:

Mass of water = 52 kg

Initial temperature
`T_(1)` = 68 °F = 20° c

Final temperature
`T_(2)` = 212 °F = 100° c

Specific heat of water
`C = 4.186 (KJ)/(kg c)`

Now heat transfer Q = m × C × (
`T_(2)` -
`T_(1)` )

⇒ Q = 52 × 4.186 × ( 100 - 20 )

⇒ Q = 17413.76 KJ

This is the amount of energy added to rise the temperature.