Question

3x-8<=23 AND -4x+26>=6

Answer 1

Step 1: Solve for x in the first equation

`3x-8+8\leq 23+8`

`3x\leq 31`

`3x/3\leq 31/3`

`x\leq (31)/(3)`

Step 2: Solve for x in the second equation

`-4x + 26-26 \geq 6-26`

`-4x\geq -20`

`-4x/-4\geq -20/-4`

Since you divide by a negative, you must flip the sign.

`x\leq 5`