Answer:
The electric field at any point not on either surface is 11.28 N/C.
Step-by-step explanation:
Given that,
The surface charge density of first sheet,

The surface charge density of second sheet,

The relation between the electric field and the surface charge density is given by :

For first sheet :

For second sheet,

The net magnitude of the electric field at any point not on either surface is given by :

So, the electric field at any point not on either surface is 11.28 N/C.