Question

A 2400.-gram sample of an aqueous solution contains 0.012 gram of nh3. What is the concentration of nh3 in the solution

Answer 1

Answer : The concentration of
`NH_3` in the solution is,
`2.94* 10^(-4)M`

Explanation :

First we have to calculate the volume of aqueous solution that is water.

Density of water = 1.00 g/mL

Mass of water = 2400 g

`\text{Volume of water}=(Mass)/(Density)=(2400g)/(1.00g/mL)=2400mL`

Now we have to calculate the concentration of ammonia solution.

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

`\text{Molarity}=\frac{\text{Mass of }NH_3* 1000}{\text{Molar mass of }NH_3* \text{Volume of solution (in mL)}}`

Molar mass of
`NH_3` = 17 g/mole

Now put all the given values in this formula, we get:

`\text{Molarity}=(0.012g* 1000)/(17g/mole* 2400mL)=3.12mole/L=2.94* 10^(-4)M`

Therefore, the concentration of
`NH_3` in the solution is,
`2.94* 10^(-4)M`