Answer:
5.7 grams is the mass carbon dioxide gas inside a 3.0-L balloon.
Step-by-step explanation:
Using ideal gas equation:
PV = nRT
where,
P = Pressure of carbon dioxide gas =
![1.0 atm](https://img.qammunity.org/2021/formulas/chemistry/high-school/srkwrwq4dp6jpf58n43ydwrvqgtziy31s9.png)
V = Volume of carbon dioxide gas = 3.0 L
n = number of moles of carbon dioxide gas = ?
R = Gas constant = 0.0821 L.atm/mol.K
T = Temperature of carbon dioxide gas =0°C = 0+273= 273 K
Putting values in above equation, we get:
![(1.0 atm)* 3.0 L=n* (0.0821L.atm/mol.K)* 273 K\\\\n=0.13 mol](https://img.qammunity.org/2021/formulas/chemistry/high-school/xjomosxzu4ls5few1fl66roexlxekvqdg0.png)
Mass of 0.13 mole carbon dioxide gas :
= 0.13 mol × 44 g/mol = 5.7 g
5.7 grams is the mass carbon dioxide gas inside a 3.0-L balloon.