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Point (k, -2) lies on the line whose equation is x-3 y=7. What is the value of k?

User Anduril
by
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1 Answer

2 votes

Answer:

k =1

Explanation:

x-3y = 7

Let y = -2 since we have the point (k, -2)

x -3(-2) =7

x+6 =7

Subtract 6 from each side

x+6-6=7-6

x =1

The point is (1,-2)

User Peter Peng
by
7.6k points

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