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The total pressure for a mixture of N2O4 and NO2 is 1.5atm. If Kp = 7.1 at 25°C, calculate the partial pressure of each gas in the mixture. (HINT 1.5 = 2pNO2 + pN2O4) 2NO2 (g) = N2O4 (g)

User Lkraav
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Answer:


N_(2) O_(4) : 0.5 atm and
N_{} O_(2) : 1 atm

Step-by-step explanation:

In order to calculate the partial pressure for each gas , all you need to do is multiply the mole fraction of each gas with the total pressure.

It is given that
P_(total) = 1.5 atm

The mole fraction of each gas can be calculated in the following way:


N_(2) O_(4) = moles of
N_(2) O_(4) ÷ total moles present =
(1)/(3)


N_{} O_(2) = moles of
N_{} O_(2) ÷ total moles present =
(2)/(3)

Partial pressure of
N_(2) O_(4) : 1.5 ×
(1)/(3) = 0.5 atm

Partial pressure of
N_{} O_(2) : 1.5 ×
(2)/(3) = 1 atm

Hope that answers the question, have a great day!

User Victor Kushnerov
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