Question

The total pressure for a mixture of N2O4 and NO2 is 1.5atm. If Kp = 7.1 at 25°C, calculate the partial pressure of each gas in the mixture. (HINT 1.5 = 2pNO2 + pN2O4) 2NO2 (g) = N2O4 (g)

Answer 1

`N_(2) O_(4)` : 0.5 atm and
`N_{} O_(2)` : 1 atm

Step-by-step explanation:

In order to calculate the partial pressure for each gas , all you need to do is multiply the mole fraction of each gas with the total pressure.

It is given that
`P_(total)` = 1.5 atm

The mole fraction of each gas can be calculated in the following way:

`N_(2) O_(4)` = moles of
`N_(2) O_(4)` ÷ total moles present =
`(1)/(3)`

`N_{} O_(2)` = moles of
`N_{} O_(2)` ÷ total moles present =
`(2)/(3)`

Partial pressure of
`N_(2) O_(4)` : 1.5 ×
`(1)/(3)` = 0.5 atm

Partial pressure of
`N_{} O_(2)` : 1.5 ×
`(2)/(3)` = 1 atm

Hope that answers the question, have a great day!