Answer:
14.9 g is the ideal yield of Cu(NO₃)₂
Step-by-step explanation:
Reactants for the reaction: Cu and AgNO₃
Products: Copper nitrate and Ag
The balanced reaction is: Cu(s) + 2AgNO₃(aq) → 2Ag (s) + Cu(NO₃)₂
As the silver nitrate is in excess, the Cu will be the limiting reagent.
We convert the mass to moles → 5.05 g . 1 mol/ 63.55 g = 0.0794 moles
Ratio is 1:1, so 0.0794 moles will produce 0.0794 moles of Cupper(II) nitrate. We convert the moles to mass, and that value will be the theoretical yield.
0.0794 mol . 187.55 g /1 mol = of Cu(NO₃)₂