Question

Suppose the collision speed is 20 mph and the rebound speed is 5 mph. The energy ratio is?

Answer 1

The energy ratio is
`16:1.`

Step-by-step explanation:

The kinetic energy of the 20mph object is

`K_1 = (1)/(2)m(20mph)^2`,

and the kinetic of the same abject at 5mph is

`K_2 = (1)/(2)m(5mph)^2;`

therefore, the ratio of
`K_1` to
`K_2` is

`$(K_1)/(K_2) = ((1)/(2)m(20mph)^2)/( (1)/(2)m(5mph)^2) = ((20mph)^2)/((5mph)^2) =(16)/(1) $`

Thus, the energy ratio is
`K_1:K_2 = 16:1`.