Answer:
213.79mL
Explanation:
C1 (initial concentration) = 6M
V1 (initial volume) = 200mL
C1 (final concentration) = 2.9M
V2 (final volume) =?
Using the dilution formula C1V1 = C2V2, the final volume can be obtain as follow:
C1V1 = C2V2
6 x 200 = 2.9 x V2
Divide both side by 2.9
V2 = (6 x 200) /2.9
V2 = 413.79mL
To obtain the volume added, we'll take the difference between the final volume and the initial volume. This is illustrated below:
Volume added = V2 — V1
Volume added = 413.79 — 200
Volume added = 213.79mL
Therefore, the volume of water added to the solution is 213.79mL