Question

A dart gun consists of a horizontal spring with k = 52 Newtons/m that is compressed 43

the gun is cocked. What is the initial acceleration of a 75-g dart when the gun is fired?

Answer 1

`299 m/s^2`

Step-by-step explanation:

When a spring is compressed, the force exerted by the spring is given by:

`F=kx`

where

k is the spring constant

x is the compression of the spring

In this problem we have:

k = 52 N/m is the spring constant

x = 43 cm = 0.43 m is the compression

Therefore, the force exerted by the spring on the dart is

`F=(52)(0.43)=22.4 N`

Now we can apply Newton' second law of motion to calculate the acceleration of the dart:

`F=ma`

where

F = 22.4 N is the force exerted on the dart by the spring

m = 75 g = 0.075 kg is the mass of the dart

a is its acceleration

Solving for a,

`a=(F)/(m)=(22.4)/(0.075)=299 m/s^2`