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The magnetic field 0.02 m from a wire is 0.1 T. What is the magnitude of the magnetic field 0.01 m from the same wire?

1 Answer

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Answer:

The magnetic field at 0.01m from the wire is 0.2T.

Step-by-step explanation:

The magnetic field
B at a distance
R due to a straight wire carrying a current
I is


B = (\mu_oI )/(2\pi R),

where
\mu_o = 4\pi*10^(-7) m\cdot kg\cdot s^(-2) A^(-2) is the magnetic constant.

Now, we are told that the magnetic field from a wire at
R = 0.02m is
B = 0.01; therefore,


0.1T = ((4\pi*10^(-7))I )/(2\pi (0.02m)),

solving for
I we get:


I = 10,000A

which is the current through the wire.

Now, the magnetic field
B of the wire due to this current at the distance of
R = 0.01m is


B =((4\pi*10^(-7))(10,000))/(2\pi (0.01))


\boxed{B = 0.2 T}

Thus, the magnetic field at 0.01m from the wire is 0.2T.

User BergP
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