Question

Find the distance between the radical form (3,9) and (0,2)

Answer 1

The distance between these two points is
`√(58)`

Explanation:

Step 1: Find the distance using the distance formula

`d = √((x_2-x_1)^2+(y_2-y_1)^2)`

Plug in 0 for
`x_2`, 3 for
`x_1`, 2 for
`y_2`, 9 for
`y_1`

`d = √((0-3)^2+(2-9)^2)`

`d = √((-3)^2+(-7)^2)`

`d=√(9+49)`

`d=√(58)`

Answer: The distance between these two points is
`√(58)`

Answer 2

Hey there!

`\large\boxed{√(58)}`

Use the pythagorean theorem:

a² + b² = c²

a will be rise and b will be run.

Distance between 9 and 2 is 7.

Distance between 3 and 0 is 3.

Plug those into the equation.

7² + 3² = c²

Square.

49 + 9 = c²

Add.

58 = c²

Square root both sides.

√58 = c

This is the distance in radical form.

Hope this helps!