Question

A brand of cereal had 1.21.2 1.2 1, point, 2 milligrams (mg)(\text{mg}) (mg) left parenthesis, start text, m, g, end text, right parenthesis of iron per serving. Then they changed their recipe so they had 1.8 mg1.8\,\text{mg} 1.8mg 1, point, 8, start text, m, g, end text of iron per serving.

Answer 1

The percent increase in iron is 50 %.

Explanation:

The percentage increase is given by

Firstly we find the increase or the difference in the amount of iron per serving as follows

Increase in iron per serving = Final iron content - Initial iron content

= 1.8 mg of iron - 1.2 mg of iron= 0.6 mg of iron

Next, we divide the increase by the initial or original iron content which is

1.2 mg of iron per serving

Hence
`\frac{Increase \hspace{0.05cm} in \hspace{0.05cm} iron \hspace{0.05cm} per \hspace{0.05cm} serving}{Initial \hspace{0.05cm} iron \hspace{0.05cm} content} = \frac{0.6 \hspace{0.05cm} mg}{1.2\hspace{0.05cm} mg} = 0.5`

Next, we multiply by 100 to get the value as a percentage,

That is 0.5 × 100 = 50 %

The percent increase in iron = 50 %.