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Can someone help please ❤️❤️

Can someone help please ❤️❤️-example-1
User Glo
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1 Answer

4 votes

(A) The mean is 82

(B) The mean absolute deviation is approximately 9.71

(D) The IQR is 11

Step-by-step explanation:

(A) 89, 87, 54, 78, 87, 99, 80

Mean of the data =
(sum of the data)/(total number of data)


Mean = (89 + 87+54+78+87+99+80)/(7) \\\\Mean = (574)/(7) \\\\Mean = 82

Therefore, mean of the data is 82

(B) The mean absolute deviation, MAD is

data - 54, 78, 80, 87, 87, 89, 99

Mean of the data, x' is 82

|x - x'| : 54 - 82 = 28

78 - 82 = 4

80 - 82 = 2

87 - 82 = 5

87 - 82 = 5

89 - 82 = 7

99 - 82 = 17

Total of |x - x'| = 68

MAD = |x - x'| / n

MAD = 68/7

MAD = 9.71

(D) IQR is the interquartile range

Data = 54, 78, 80, 87, 87, 89, 99

IQR = median of lower quartile range - median of upper quartile range

IQR = 89 - 78

IQR = 11

User Janitha Tennakoon
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